b^2-5b+25=0

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Solution for b^2-5b+25=0 equation:


Simplifying
b2 + -5b + 25 = 0

Reorder the terms:
25 + -5b + b2 = 0

Solving
25 + -5b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-25' to each side of the equation.
25 + -5b + -25 + b2 = 0 + -25

Reorder the terms:
25 + -25 + -5b + b2 = 0 + -25

Combine like terms: 25 + -25 = 0
0 + -5b + b2 = 0 + -25
-5b + b2 = 0 + -25

Combine like terms: 0 + -25 = -25
-5b + b2 = -25

The b term is -5b.  Take half its coefficient (-2.5).
Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.
-5b + 6.25 + b2 = -25 + 6.25

Reorder the terms:
6.25 + -5b + b2 = -25 + 6.25

Combine like terms: -25 + 6.25 = -18.75
6.25 + -5b + b2 = -18.75

Factor a perfect square on the left side:
(b + -2.5)(b + -2.5) = -18.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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